If the cost of banana is increased by Rs 1 per dozen ,one can get 2 dozens less for Rs 840 .find the original cost of one dozen banana.
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Assume the original cost of a dozen bananas is X.
As total cost of all bananas is RS. 600, the no. of bananas will be 600/X
Now, u can get 3 dozen less, that is 600/X - 3 bananas if price is increased by 10, that is X+10.
Hence as total cost remains the same,
(X+10)(600/X -3)= 600
Upon solving it like a quadratic equation, you get the answers -50 and 40.
As price can never be negative, the price per dozen I'd RS. 40
Hope this helps!
As total cost of all bananas is RS. 600, the no. of bananas will be 600/X
Now, u can get 3 dozen less, that is 600/X - 3 bananas if price is increased by 10, that is X+10.
Hence as total cost remains the same,
(X+10)(600/X -3)= 600
Upon solving it like a quadratic equation, you get the answers -50 and 40.
As price can never be negative, the price per dozen I'd RS. 40
Hope this helps!
saiyra98:
how 600 came
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