if the cube of 1+3/5 = 4 + x/125 then find the value of x
please answer with step by step working
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Answered by
4
Answer:
Step-by-step explanation:
Given equation
(\sqrt[3]{3/5})^{2x+1}=125/27
then simplify the equation
\left ( 3/5 \right )^{(2x+1)/3}=\left ( 5/3 \right )^{3}
convert same base form \left ( a/b \right )^{m}=\left ( b/a \right )^{-m}
\left ( 3/5 \right )^{(2x+1)/3}=\left ( 3/5 \right )^{-3}
if base is same then compare the power and find out the value of x
\left ( 2x+1 \right )/3=-3
2x+1=-9
2x=-10
x=-5
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Answered by
0
Answer:
X=-5 IS THE SOLUTION
Step-by-step explanation:
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