if the cube roots of unity are 1,w,w2 then 1+w+w2=
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Answer:
The roots of the equation (x−1)
3
+8=0⇒(x−1)=(−2)(1)
1/3
⇒x−1=−2or−2w
2
or −2ω
⇒x=−1or1−2w
2
. or 1−2ω
Step-by-step explanation:
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23
option are 1
tell options
0,-1 and w
options are 1,-1,0 and w
The roots of the equation (x−1)3+8=0⇒(x−1)=(−2)(1)1/3
⇒x−1=−2or−2w2 or −2ω
⇒x=−1or1−2w2. or 1−2ω
⇒x−1=−2or−2w2 or −2ω
⇒x=−1or1−2w2. or 1−2ω
hey I have posted that...why are you commenting here now :(
I've also posted the same
my first answer was wrong again I edited
ohhh ok
Answered by
0
;)
The roots of the equation (x−1)^3 +8=0
⇒(x−1)=(−2)(1)^1/3
⇒x−1=−2or−2w^2 or −2ω
⇒x=−1or1−2w^2 . or 1−2ω
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