Question

if the current flowing in a coil of resistance 90 ohm is to be reduces by 90% what value of resistance that should be connected in parallel with it is​

Answer 1

See that reduced current should pass through shunt or the resistance that is connected in parallel

So let initial current =I

Final current = I -90% of I = 0.1*I

So now 0.1*I*90 = 0.9I*R

R=10 ohm

Explanation: