if the current I though a resistor is increased by 100%, then find the increase in
power dissipated .
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Answer:
Let the original value of current is I ampere.
The new value of current I' =I+100%I=2I.
Now, the new power P =I²R=4I.R=4P.
So, the change in power = P' −P=3P
Therefore, the change in power in terms of percentage is 300%.
Hence, the increase in power dissipated will be 300%.
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