If the current I through a resistor is increased by 100%(temperature remains unchanged), the increase in power dissipated is,
a) 100%
b) 200%
c) 300%
d) 400%
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Answers
Answered by
11
Answer:
(d) 300%
Explanation:
p=I²R
I(n)=I+I= 2I (coz increased by itself)
P = (2I)²R
=4I²R
=4P
4P-P = 3P
hence, 300%
Answered by
1
Answer: a) 100 percent
Explanation:
P=VI
According to question, new current is double (as it increases by 100 percent)
Now,
P'=V(2i)
P'=2VI
Therefore,
P'=2P
That is 100 percent
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