If the current I through a resistor is increased by 100% ( assume temp remains unchanged ) the increase in power dissipated will be
100%
200 %
400 %
300 %
Answers
Answered by
7
300%...
As power=Isq.rt
Increased curren=2I
So new power=(2I)sq.rt
=4Isq.rt
As power=Isq.rt
Increased curren=2I
So new power=(2I)sq.rt
=4Isq.rt
Answered by
7
Answer:
I think your answer is 300%
please thanks me
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