if the current I through a resistor is increased by 100% the increase in power dissipated will be
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Let the original value of current is I ampere.
The new value of current I′=I+100%I=2I.
Now, the new power P′=I′2
R=4I
R=4P.
So, the change in power = P′−P=3P
Therefore, the change in power in terms of percentage is 300%.
Hence, the increase in power dissipated will be 300%.
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