Question

if the current i through the resistor is increased by 100%(temperature kept constant),the increase in power dissipated will be​

Answer 1

Answer:

300 percent

Explanation:

Let the original value of current is I ampere.

The new value of current I′=I+100%I=2I.

Now, the new power P′=I′2R=4I.R=4P.

So, the change in power  = P′−P=3P

Therefore, the change in power in terms of percentage is 300%.

Hence, the increase in power dissipated will be 300%.

Hope this helps you

Please mark as brainliest