If the current I through the resistor is increased by 100%( assume the temperature remain incharge), the increase in power dissipated.
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If the current is increased by 100% then the value of current will be doubled
Power P = I^2 R
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Answer:
Let the original value of current is I ampere.
The new value of current I′=I+100%I=2I.
Now, the new power P′=I′2
R=4I
R=4P.
So, the change in power = P′−P=3P
Therefore, the change in power in terms of percentage is 300%.
Hence, the increase in power dissipated will be 300%.
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