Question

if the curved surface area of a solid right circular cylinder of height h and radius r is one third of it's surface area ,then. h=1/3r. ,h=1/2r ,h=r. ,h=2r

Answer 1

Answer:

$h=\frac{1}{2}r$

Step-by-step explanation:

Formula used:

Curved surface area of cylinder

$=2\pi\:r\:h$ square units

Total surface area of cylinder

$=2\pi\:r(h+r)$ square units

Given:

$C.S.A=\frac{1}{3}T.S.A\\\\2\pi\:r\:h=\frac{1}{3}[2\pi\:r(h+r)]\\\\h=\frac{1}{3}(h+r)\\\\3h=h+r\\\\3h-h=r\\\\2h=r\\\\h=\frac{1}{2}r$