Question

If the de-Broglie wavelength corresponded to translational kinetic energy of H atom at 768k the circumference of the fourth Bohr orbit will be​

Answer 1

Answer: Circumference = 16Å

Given: Electron is revolving around 4 orbit

To find: Circumference of the fourth orbit

Explanation:

De Broglie wavelength of atom = 4A (Given)

A de Broglie wavelength is the wavelength, which is possessed by all the particles. As the dual property of the electron, it determines the probability density of finding the object at a given point of the space

Using the equation - mvr=nh/2π

= mvr =nh/2π

= 2πr = nh/mv

= 2πr = n× λ { Since λ =h/mv}

Since, n=4 and wavelength = 4Å

Thus,  

= 2πr = 4×4Å

= 16Å

Circumference of 4th orbit = 16Å

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