Question

if the de-broglie wavelength of a particle of mass m is 100 times its velocity then its velocity then its value in terms of its mass(m) and planck's constant(h) is

Answer 1

Answer:

10root h/m

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Answer 2

Answer:

λ=

λ= mv

λ= mvh

λ= mvh

λ= mvh

λ= mvh According to given question λ=100v

λ= mvh According to given question λ=100v100v=

λ= mvh According to given question λ=100v100v= mv

λ= mvh According to given question λ=100v100v= mvh

λ= mvh According to given question λ=100v100v= mvh

λ= mvh According to given question λ=100v100v= mvh

λ= mvh According to given question λ=100v100v= mvh so v

λ= mvh According to given question λ=100v100v= mvh so v 2

λ= mvh According to given question λ=100v100v= mvh so v 2 =

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100m

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10 m

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10 mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10 mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10 mh

λ= mvh According to given question λ=100v100v= mvh so v 2 = 100mh λ=100v λ=10 mh

I hope it helps u ☺️❣❣✌️.......