Question

If the de broglie wavelength of a particle of mass m is 100 times its velocity then its value in terms of its mass and planck's constant is

Answer 1

Final Answer : $10\sqrt{\frac{h}{m}}$

Steps:
1) Magnitude :
$\lambda = 100 v \\ => v = \frac{\lambda}{100}$

2) We know by,
De-Brogie Relation:
$\lambda = \frac{h}{mv} \\ =>\lambda = \frac{h}{m \frac{\lambda}{100}} \\ => \lambda^2 = \frac{100h}{m} \\ => \lambda =10 \sqrt{\frac{h}{m}}$

Hence, We got Wavelength of particle as :
$\boxed{ \lambda = 10 \sqrt{ \frac{h}{m} } \: units }$

Answer 2

Hope this helps. Sorry for the bad handwriting.