Question

If the de Broglie wavelength of electron in nth
Bohr orbit in hydrogen atom is equal to 1.5 ×3.14a
(a, is Bohr radius), then the value of n/z is​

Answer 1

Answer:

Hope this will help you.

Answer 2

The value of $\frac{n}{z}$ is 0.75.

Explanation:

According to De-Broglie wavelength, relation between wavelength and momentum is as follows.

       $\lambda = \frac{h}{m \nu} = \frac{h}{p}$

where,    $\nu$ = velocity

               m = mass,         h = Planck's constant

                p = momentum

Also according to De-Broglie wavelength,    

           $2 \pi r \gamma = n \lambda$

or,        $2 \pi d_{o} \frac{n^{2}}{z} = n \lambda$    

Putting the given values into the above formula as follows.

            $2 \pi d_{o} \frac{n^{2}}{z} = n \lambda$    

      $2 \pi a \frac{n^{2}}{z} = n \times 1.5 \times 3.14 \times a$    

                $\frac{n}{z}$ = $\frac{1.5}{2}$

                               = 0.75

Therefore, the value of $\frac{n}{z}$ is 0.75.