if the denominator of a fraction added to numerator and numerator subtracted from denominator the fraction becomes 11/3 if the denominator exceeds the numerator by three . find the fraction
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Answer:
let the numerator be x and denominator is x+3
as per the given condition
therefore the fraction if x/x+3
again denominator is added to numerator and numerator subtracted from denominator
fraction becomes (x + x + 3)/(x +3 - x) = 11/3
=> (2x + 3)/3 = 11/3
=> 33 = 3 (2x + 3)
=> 33 = 6x + 9
=> 33-9 = 6x
=> 24 = 6x
therefore x = 24/6 = 4
fraction is going to be x/x+3
substituting x = 4
we get 4/4+3 = 4/7
answer is 4/7
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