If the denominator of a fraction exceeds the numerator by 2. If the numerator is decreased by 1 and the denominator is increased by 3, the value of the resulting fraction is 1/2. Find the fraction.
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Given :-
- The denominator of a fraction exceeds the numerator by 2. If the numerator is decreased by 1 and the denominator is increased by 3
To find :-
- Required fraction
Solution :-
Let the numerator be x then denominator be (x + 2)
- If the numerator is decreased by 1 and the denominator is increased by 3, the value of the resulting fraction is 1/2.
As per given condition
→ (x - 1)/(x + 2) + 3 = ½
→ x - 1/x + 2 + 3 = ½
→ x - 1/x + 5 = ½
→ 2(x - 1) = x + 5
→ 2x - 2 = x + 5
→ 2x - x = 2 + 5
→ x = 7
Hence,
- Required fraction
- Numerator/denominator = x/x + 2
- 7/7 + 2 = 7/9
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Answer:
according to me this will be the right answer
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