Question

If the density of a certain gas at 30°C and 768 atm pressure
is 1.35 kg/mºfind its density at STP.​

Answer 1

Answer:

We can use the formula PV = nRT.

Let us assume that V = 1 liter.

PV = nRT

n = PV/RT = (768/760 atm) x (1 L) / [(0.0821 Latm/mole K) x (303K)] = 0.0406 moles of gas 

= 1 L x (1 m³ / 1000 L) x (1.35 kg / 1 m³ ) x (1000 g / 1 kg) = 1.35 g 

Thus, MW of gas = 1.35 g / 0.0406 moles = 33.3 g/mole.

At STP, n = PV / RT = (1.0 atm) x (1 L) / [(0.0821 Latm/moleK) x (273K)] = 0.0446 moles 

= 0.0446 moles x (33.3 g / mole) x (1 kg / 1000 g) = 0.00149 kg

= 0.00149 kg / 1 L x (1000 L / 1 m³) = 1.49 kg / m³

Answer 2

From green answer is write