If the density of a solution is 3.12 g mL⁻¹, the mass of 1.5 mL solution in significant figures is......
(a) 4.7 g
(b ) 4680 ×10⁻³ g
(c) 4.680 g
(d) 46.80 g
Answers
Density of solution = 3.12 g mL-1
Volume of solution =1.5 mL
Mass of solution = Volume x Density
= 1.5 mL x 3.12 g mL-1
= 4.68 g = 4.7 g (up to 2 significant figures)
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Answer:
(a) 4.7 g
Explanation:
Density is described as mass consistent with volume,
d = m/v
Rearranging the above equation,
m = d X v
Given,
d = 3.12 g mL−1
v = 1.five mL
Thus,
m = 3.12 x 1.five = 4.sixty eight g
By rounding to 2 big figures ( on account that withinside the multiplication is the least range of big determine )
We get 4.7 g
Thus option (a) is accurate.
Incorrect alternatives (b), (c), (d)
Since we want a solution with big determine the opposite alternatives are incorrect.
Final Answer
The accurate solution is,
(a) 4.7 g
So,If the density of an answer is 3.12 g mL⁻¹, the mass of 1.five mL answer in big figures is 4.7.
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