If the density of Earth increases by 20% & radius decreases by 20% then the new vslue of "g" on the surface of Earth will be?
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g = GM / R²
= G × (4/3 π × R³ d) / R² ………[∵ Mass = Volume × Density]
= 4πGdR/3
From above relation
g ∝ dR
g₂/g₁ = (d₂ / d₁) × (R₂ / R₁)
g₂ = g₁ × (d₂ / d₁) × (R₂ / R₁)
g₂ = 9.8 m/s² × (120 / 100) × (80 / 100)
g₂ = 9.408 m/s²
Acceleration due to gravity on surface of earth will be 9.408 m/s²
= G × (4/3 π × R³ d) / R² ………[∵ Mass = Volume × Density]
= 4πGdR/3
From above relation
g ∝ dR
g₂/g₁ = (d₂ / d₁) × (R₂ / R₁)
g₂ = g₁ × (d₂ / d₁) × (R₂ / R₁)
g₂ = 9.8 m/s² × (120 / 100) × (80 / 100)
g₂ = 9.408 m/s²
Acceleration due to gravity on surface of earth will be 9.408 m/s²
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1
Explanation:
The three most common methods are basin irrigation, border irrigation and furrow irrigation. Water is typically introduced at the highest point or along the edge of a field, which allows covering the field by overland flow.
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