Question

If the density of earth increases by 20% and radius decreases by 20% then the new value of “g” on

the surface of earth will be :​

Answer 1

Answer:

Dear Student ,

we know that ,acceleration due to gravity of earth is

ge=GMeRe2=G43πRe3ρRe2=43πReGρNow when density of earth is increased by 20% and radius is decreased by 20% then ,ρ'=(ρ+20ρ100)=6ρ5and Re'=(Re−20Re100)=4Re5So the new value of g on the surface of the earth is ,ge'=43πRe'Gρ'=43π4Re5G6ρ5=242543πReGρ=2425ge

Regards