If the density of iron is 7900 km/m cube, then it's relative density is?
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Given, density of iron = 7900 kg ${{m}^{-3}}$
Density of water = 1000 kg ${{m}^{-3}}$
Relative density = Density of Iron / Density of water = 7900 kg ${{m}^{-3}}$ /
1000 kg ${{m}^{-3}}$ = 7.9
As the relative density of an iron object is greater than density of water, so it will sink to bottom...
hope it helps..
Density of water = 1000 kg ${{m}^{-3}}$
Relative density = Density of Iron / Density of water = 7900 kg ${{m}^{-3}}$ /
1000 kg ${{m}^{-3}}$ = 7.9
As the relative density of an iron object is greater than density of water, so it will sink to bottom...
hope it helps..
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