Question

if the density of metanol is 0.793 kg/l. calculate its molarity​

Answer 1

Answer:

Mass of methanol required is

M=Volume of solution × Molariy of solution×Molar mass of methanol

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793=25.22 mL.

Answer 2

Answer:

if the density of methanol is 0.793kg/L, what is its volume needed for making 2.5L of its 0.25M solution? =2.5×0.25×32=20 g. =25.22