Question

If the density of methanol is 0.793 kg L', what is its volume needed for making 2.5 L of its 0.25M solution. ​

Answer 1

Answer:

Given

The density of methanol =0.793kg/L

The mass of methanol =

CH3OH

12 + 1 (3) + 16 + 1.

12 + 3 + 16 + 1.

15 + 17.

32u.

Let x g of methanol (molar mass = 32g) be required to prepare a 0.25 Molar solution of methanol.

Therefore we have 0.25 = (x/32) X (1/2.5)

x = 20g = 0.02 Kg

Now density = Mass/ Volume

We are given that the density of methanol is 0.793 KgL-1.

Therefore, Volume = Mass/ Density =

Volume of methanol needed = mass/density

=20/0.793

=25.22 mL.

Answer

Therefore 0.025 Litres 25.22 mL or of methanol would be required.