Question

If the density of methanol is 0.8 kg/L, what is its volume needed for making
2 L of its 0.5 M solution? (molar mass = 32 g/
mol) *
O 200 ml
0.2 mL
20 mL
о
0.02 mL

Answer 1

Answer:

Molarity = (wt/Mol.wt) x (1/ V in L)

Mol.wt of CH3OH is 32

For 0.4M= (wt/32) x (1/2.5) => wt= 32

Quantity of methanol required is 32gm.

As given solution has density of 0.8kg/L i.e 800gm of methanol is present in 1000ml. So for 32 gm we need 40ml of above solution.