Question

If the density of water is 1.00gcm^3.Find the number of molecules present in 180gcm^3 of water​

Answer 1

Answer:

Hello

Explanation:

Thank you so much for 10 points

Answer 2

Explanation:

1 mole of a molecule = it's molecular mass= avogadro number of molecules(6.022 *10^23)= volume at stp(22.4L)

And for an atomic substance

1 mole of atoms = it's atomic mass= avogadro number of atoms (6.022 *10^23)= volume at stp(22.4L)

If density is given then multiply mass with density to get the volume for which in this case is 180 gram/cm3

Here, two variables are considered mass and molecules so we take the first formula:

For water, 18 g of H2O has 6.022*10^23

Therefore, 180g of H2O has 10*6.022*10^23

=6.022*10^24 molecules of H2O.