Question

If the density of water is 1 gm/cm”, then the volume
occupied by one molecule of water is approximately-
(A) 18 cm
(B) 22400 cm3
(C) 6.02 x 10-23 cm (D) 3.0 × 10-23 cm3​

Answer 1

Answer:

Hey !! the ans. is option D)

Explanation:

We know the formula....

wt./M.wt.= no.of molecules/NA

NA = 6.022x10^23

M.wt.of water=18

so by putting the given values in this formula we will get...

wt./18=1/6.022x10^23

wt.=18/6.022x10^23

wt.=2.98x10^-23

now..

density =m/v

1=2.98x10^-23/v

v=2.98x10^-23 ml

which is approx to...

=3.0x10^-23 ml

Thankuu