Question

If the density of water is 1g/cm3 then the volume occupied by one molecule of water is

Answer 1

Answer:

mass of one molecule of water= 18÷6.023×10^-23 g

Volume of one molecule of water:-

v=m/d

=2.9885/1× 10^-23 cm3

= 2.9885×10^10^-23 cm3