if the depletion of oxygen is found to be 5ppm after incubating a 2.5% solution of sewage sample for 5 days at 20 degree , bod of the sewage is?
Answers
Answered by
0
Answer:
Dilution factor =(Vol of diluted sample/Vol of in diluted sewage sample). DO initial-DO final means depleted oxygen content. Therefore, BOD = 5 * (100/2) = 250ppm.
Similar questions