English, asked by divyabhatt584, 7 months ago

if the depletion of oxygen is found to be 5ppm after incubating a 2.5% solution of sewage sample for 5 days at 20 degree , bod of the sewage is?​

Answers

Answered by Prabhaseessingh
0

Answer:

Dilution factor =(Vol of diluted sample/Vol of in diluted sewage sample). DO initial-DO final means depleted oxygen content. Therefore, BOD = 5 * (100/2) = 250ppm.

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