If the derivative of a function f is twice the function find f
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y ' = 2y ⇒ f ' (x) = 2 f(x) ⇒ f'(x) / f(x) = 2
integrating both sides
ln | f(x) | = 2x + c
f(x) = e ^ ( 2x + c)
hope this helps.
y ' = 2y ⇒ f ' (x) = 2 f(x) ⇒ f'(x) / f(x) = 2
integrating both sides
ln | f(x) | = 2x + c
f(x) = e ^ ( 2x + c)
hope this helps.
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