Question

if the diagnalosis of a parallelogram are eqal then show that it is a rectangle
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Answer 1

Step-by-step explanation:

Given that the diagonals AC and BD of parallelogram ABCD are equal in length . Consider triangles ABD and ACD. ∠BAD + ∠CDA = 180° [Adjacent angles of a parallelogram are supplementary.] ... Therefore, parallelogram ABCD is a rectangle since a parallelogram with one right interior angle is a rectangle

Answer 2

Answer:

yes I can prove it but u have to join my Google meet