If the diagonal BD of quadrilateral ABCD bisects angle B and angle D probe that AB/BC=AD/CD
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Given: diagonal BD bisects angle B and angle D
To prove: AB/BC= AD/CD
Proof: in triangle ABD and triangle CBD
angle ABD= angle CBD (BD bisects angle B)
angle ADB= angle CDB ( BD bisects angle D)
therefore, triangle ABD similar to triangle CBD (AA)
so, AB/BC = AD/CD (cpst, i.e., coressponding parts of similar triangle)
hence proved.........
To prove: AB/BC= AD/CD
Proof: in triangle ABD and triangle CBD
angle ABD= angle CBD (BD bisects angle B)
angle ADB= angle CDB ( BD bisects angle D)
therefore, triangle ABD similar to triangle CBD (AA)
so, AB/BC = AD/CD (cpst, i.e., coressponding parts of similar triangle)
hence proved.........
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