Question

If the diagonal of a cube is 11√3, then what is the total surface area of cube?

Answer 1

$diagonal \: of \: cube = \sqrt[side]{3} \\ \sqrt[11]{3} = \sqrt[side]{3} \\ side = 11cm \\ surface \: area \: of \: cube = {6 \times side}^{2} \\ \: \: \: = 6 \times 11 \\ = 66 {cm}^{2}$

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