if the diagonal of a llgm are equal,then show that it is a rectangle
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#Heya Yash is here for help you#
#Please mark as Brainliest answer#
In ΔABC and ΔDCB,
AB = DC (Opposite sides is equal)
BC = BC (Common)
AC = DB (Given)
∴ ΔABC ≅ ΔDCB (By SSS)
⇒ ∠ABC = ∠DCB
Measures of angles transversal is 180º.
∠ABC + ∠DCB = 180º (AB || CD)
⇒ ∠ABC + ∠ABC = 180º
⇒ 2∠ABC = 180º
⇒ ∠ABC = 90º
ABCD is a parallelogram and one of its interior angles is 90º ABCD is a rectangle
#Please mark as Brainliest answer#
#Please mark as Brainliest answer#
In ΔABC and ΔDCB,
AB = DC (Opposite sides is equal)
BC = BC (Common)
AC = DB (Given)
∴ ΔABC ≅ ΔDCB (By SSS)
⇒ ∠ABC = ∠DCB
Measures of angles transversal is 180º.
∠ABC + ∠DCB = 180º (AB || CD)
⇒ ∠ABC + ∠ABC = 180º
⇒ 2∠ABC = 180º
⇒ ∠ABC = 90º
ABCD is a parallelogram and one of its interior angles is 90º ABCD is a rectangle
#Please mark as Brainliest answer#
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