Question

if the diagonal of a parallelogram are equal, then show that it is a rectangle ​

Answer 1

If the diagonals of a parallelogram are equal, then show that it is a rectangle. Since ABCD is a parallelogram and one of its interior angles is 900, ABCD is a rectangle

Answer 2

Hey mate,

Your answer ❤️❤️❤️

In triangle DAB and CBA,

DA =BC (opposite sides of parallelogram)

AB =AB(common )

BD=AC

By SSS,

DAB =CBA (CPCT)

DAB +CBA =180(adjacent angles of the parallelogram)

DAB +DAB =180

2DAB =180

DAB =

$\: \: \: \: \: \: \: \: \: \frac{180}{2} = 90$

In a parallelogram ABCD,

DAB =90°

Hence proved,

ABCD is a rectangle

Hope it helps you... ❤️

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