if the diagonal of a quadrilateral bisect each other then quadrilateral all parellelogram.prove it
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in quad. ABCD
AC And BD ARE DIAGONAL INTERSECTING AT POINT O.
DRAW DIAG. BY THIS CONDITIONS
IN TR. AOB AND TR. COD
AO=CO (AC AND BD BISECT EACH OTHER)
ANGLE'S(AOB=COD) (VERT. OPP.ANGLE.)
BO=DO
TR. AOB IS CONGRUENT TO TR.COD (BY SAS )
AB = CD (CPCT)
SIMILARLY, AD = BC (BY TAKING TR'S AOD AND BOC)
THEREFORE , OPP. SIDES OF QUAD. ARE EQUAL AND ITS DIAGONAL BISECT EACH OTHER ,
HENCE IT IS A PARALLELOGRAM
AC And BD ARE DIAGONAL INTERSECTING AT POINT O.
DRAW DIAG. BY THIS CONDITIONS
IN TR. AOB AND TR. COD
AO=CO (AC AND BD BISECT EACH OTHER)
ANGLE'S(AOB=COD) (VERT. OPP.ANGLE.)
BO=DO
TR. AOB IS CONGRUENT TO TR.COD (BY SAS )
AB = CD (CPCT)
SIMILARLY, AD = BC (BY TAKING TR'S AOD AND BOC)
THEREFORE , OPP. SIDES OF QUAD. ARE EQUAL AND ITS DIAGONAL BISECT EACH OTHER ,
HENCE IT IS A PARALLELOGRAM
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parallelogram, square, rectangle and rhombus
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