Question

If the diagonal of a rectangle is 10 cm and its width is 6 cm, find its area.​

Answer 1

Answer:

48cm²

Step-by-step explanation:

length of rectangle =

$\sqrt{ {10}^{2} - {6}^{2} }$

=√(100-36)

=√64

=8

Therefore, area of rectangle = length ×breadth

= 8cm ×6cm

= 48 cm²

Answer 2

Answer:

The area of Rectangle is 48 cm²

Step-by-step Explanations :

Given : Diagonal of Rectangle = 10cm

Width of Rectangle = 6cm

To find : Area of Rectangle = ?

Diagonal of rectangle = 10 cm and Width of Rectangle (W) = 6 cm

So,

By using Pythagoras theorem, we can say,

(Diagonal)² = (Length)² + (Width)²

Substituting the given value in above formula we get,

(10)² = (Length)² + (6)²

100 = 36 + (Length)²

100 - 36 = (Length)²

64 = (Length)²

By taking square root on both sides we get,

Length = 8 cm

Now, we know that,

Area of Rectangle = Length × Width

Substituting the value in above formula we get,

Area of Rectangle = 8 × 6

= 48 cm²

Hence the area of Rectangle is 48 cm²