Question

If the diagonal of a rhombus are 1.8cm and 2.3cm then find its area.​

Answer 1

Answer:

1/2×18/10×23/10=9×23/100=206cmsquare

Answer 2

Solution :

Let ABCD be a rhombus in which

$\rm \star \: Diagonal \: {_1} (AD )= 1.8 \: cm$

$\rm \star \: Diagonal \: {_2} (B C)= 2.3 \: cm$

$\star \sf \: Area \:of \: rhombus \: = \dfrac{d_{1} \times d_{2}}{2}$

$\sf \hookrightarrow \: \cancel\dfrac{ 1.8 \times 2.3}{ 2}$

$\sf \hookrightarrow \huge \boxed{ \sf \: 2.07 \: cm^2}$

More About Rhombus :

$\star$ A parallelogram having one pair of adjacent sides equal,is called a rhombus.

$\star$ A rhombus satisfies all the properties of a quadrilateral as well as a parallelogram.

$\star$ All sides of rhombus are equal

$\star$ The diagonals of rhombus bisect each other at right angles.

$\star$ If the diagonals of parallelogram bisect each other at right angles,it is a rhombus.