if the diagonal of a rhombus are 12cm and 16cm, find the length of each side
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Let the rhombus be ABCD
and diagonals are AC,BD
In a rhombus diagonals bisect each other
Therefore, AO=6cm and BO=8cm
AC perpendicular BD
Usin ? Pythagoras theory
AO^2+BO^2=AB^2
6^2+8^2=AB^2
AB=sq.rt.36+64
=sq.rt.100
AB=10cm
In a rhombus all sides are equal
AB=BC=CD=DA=10cm
Thank you
and diagonals are AC,BD
In a rhombus diagonals bisect each other
Therefore, AO=6cm and BO=8cm
AC perpendicular BD
Usin ? Pythagoras theory
AO^2+BO^2=AB^2
6^2+8^2=AB^2
AB=sq.rt.36+64
=sq.rt.100
AB=10cm
In a rhombus all sides are equal
AB=BC=CD=DA=10cm
Thank you
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Answered by
33
Question:-
The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus
Solution:-
we know that diagonal of rhombus,bisect each other in right angle ( 90° ).
we also know that all sides of rhombus are equal ( of equal length ).
so, now
Let rhombus is ABCD
Let, diagonal of rhombus
BD = 16 cm and AC = 12 cm
means,
OD = 8 cm and AO = 6 cm
By pythagorus theorem
To find length of AD ( and all side of rhombus )
=> (AD)² = (OD)² + (AO)²
=> (AD)² = (8)² + (6)²
=> (AD)² = 64 + 36
=> (AD)² = 100
=> AD = √100
=> AD = 10 cm
Hence length of all side of rhombus
is 10 cm.
i hope it helps you.
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