Question

if the diagonal of a rhombus are 16 cm and 12 cm then what is it's area. (step by step explanation)​

Answer 1

Step-by-step explanation:

please refer to the attachment

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Answer 2

$\underline{ \sf \large{Solution- }}$

Here it is given that,

• First diagonal of rhombus = 16 cm
• Second diagonal of rhombus = 12 cm

➢ We have to find it's area.

We know,

$\sf \implies \boxed{ \sf Area \: of \: rhombus = \dfrac{1}{2} \times d_1 \times d_2}$

• Here, d₁ = First diagonal
• d₂ = Second diagonal

Now,

$\sf \implies \dfrac{1}{ 2} \times 16 \times 12$

$\sf \implies 8 \times 12$

$\bf \implies 96 \: cm^{2}$

Therefore,

• The area of rhombus = 96 cm²

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More To Know :

⟹ Rhombus is a quadrilateral whose all sides have the same length.

⟹ Opposite sides of rhombus are parallel.

⟹ Diagonals of Rhombus bisects each other at 90°