Question

if the diagonal of a rhombus are 16cmand 30 cm find its perimeter

Answer 1

Here is your solution

Given:-

Diagonal of a rhombus are 16 cm and 30 cm

Now,

We know that diagonals of rhombus bisect each part

1st diagonal is 16cm it divide in 8 cm and 8cm.

2nd diagonal is 30 it divide in 15cm and 15cm.

We know that property of rhombus

it's Center angle is 90° in every triangle part of rhombus.

Now in triangle AOB

$AB {}^{2} = OB {}^{2} + OA {}^{2} \\ AB {}^{2} = 15 {}^{2} + 8 {}^{2} \\ AB {}^{2} = 225 + 64 \\ AB {}^{2} = 289 \\ AB = \sqrt{289} \\ AB = + - 17$

We take Distance in postive.

NOW,

AB = Side of rhombus =17Cm

We know in rhombus all sides are equal

AB = BC = CD = AD = 17

Perimeter =AB+ BC+ CD +AD

Perimeter =17+17+17+17= 68cm

I hope it helps you

Answer 2

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Your solution : ♂
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