if the diagonal of a rhombus is 20cm find its perimeter
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Step-by-step explanation:
Consider a rhombus ABCD in which the length of one diagonal AC=d1=8cm and the perimeter of the rhombus is 20cm. Let the side of the rhombus be a cm and the length of the other diagonal is d2. Formula of perimeter of rhombus is 4a where a is the side of rhombus. So, the side of the rhombus is 5cm.
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Answer:
Rhombus has 4 sides equal
2 diagonals also same
With Pythagoras theorem:
(Diagonal)²=a²+a² (a is the side of rhombus)
20^2 = 2 * a^2
400 = 2 * a^2
Dividing Both side with 2
200 = a^2
Taking square root both side
a = √200
a = 10√2
Perimeter of the rhombus
Perimeter = 4*a
=>4*10√2
=>40√2 cm
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