if the diagonal of a rhombus measure 16 cm and 30 cm find its perimeter???
please apply Pythagoras theorem
Answers
Answered by
0
d1-=16 cm
d2 = 30 cm
each diagonal bisect each other on right angle
in triangle 1
apply pythagoras theorem
AB^2 = AO^2 + BO^2
=225+64
AB^2 = 289
AB =17
peremeter = add all sides
=4 x17
ans= 68cm
d2 = 30 cm
each diagonal bisect each other on right angle
in triangle 1
apply pythagoras theorem
AB^2 = AO^2 + BO^2
=225+64
AB^2 = 289
AB =17
peremeter = add all sides
=4 x17
ans= 68cm
Attachments:
Similar questions