Question

If the diagonal of a square is 10

into sqrt of 2, find its perimeter. ​

Answer 1

Answer:

Solution: Area of the square = [Diagonal ^2]/2 =0.5* [10√2]^2 = 100 cm^2. The side of the square is 10 cm and the perimeter is 4*10 = 40 cm.

Answer 2

Answer:

40 unit

Step-by-step explanation:

Given:

• Diagonal of a square = 10√2 unit

To Find:

• What is its perimeter?

Solution:

☆ Diagonal of a square = √2 × side

hence, Side = Diagonal / √2

= 10√2/√2

= 10 unit

Now,

☆ Perimeter of a square = 4 × side

= 4 × 10

= 40 unit