If the diagonal of a square is 16/2 cm, What is the length of the side ? *
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given the length of the diagonal of the square = 16cm
by Pythagoras theorem we get,
diagonal² = side² + side² (it can be applied only for square. here diagonal is the hypotenuse and sides are the base and perpendicular respectively)
➡ 16² = 2side²
➡ 256 = 2side²
➡ 256/2 = side²
➡ 128 = side²
➡ side = √128cm or 11.3cm (approximately)
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