Math, asked by shivanshatl30, 5 months ago

If the diagonal of a square shrinks to
50
%
, then to what percentage would the area of the square shrink?

12
25
50
75

Answers

Answered by Anonymous
3

Given,

The diagonals shrinks to 50%

To find,

Percentage shrink of the area of the square.

Solution,

Let, the length of the diagonal = x unit

[ Assume, x as a variable to do the further mathematical calculations.]

Initial length of one side of the square = x/✓2 unit

Initial area of the square = (x/✓2)² = x²/2 sq.unit

Now,

Final length of the diagonal = x - (x×50/100) = x-x/2 = x/2 unit

Final length of the side of the given square = x/2 ÷ ✓2 = x/2✓2 unit

Final area = (x/2✓2)² = x²/8 sq.unit

Percentage decrease = 100 × (x²/8 ÷ x²/2) = 100 × (x²/8 × 2/x²) = 100/4 = 25%

Hence,25% of the area will be decreased.

Answered by pulakmath007
14

\displaystyle\huge\red{\underline{\underline{Solution}}}

FORMULA TO BE IMPLEMENTED

 \sf{Length  \: of \:  the \:  side \:  of \:  a \:  square }

 =   \displaystyle \:  \sf{\frac{Length \: of  \: the \: diagonal \: }{ \sqrt{2} } }

GIVEN

If the diagonal of a square shrinks to 50 %

TO DETERMINE

The percentage in which the area of the square shrink

CALCULATION

Let x be the side of the square

Then the area of the square is

 \sf{ \: =  {x}^{2} \: }

Now the length of the diagonal

 =   \displaystyle \:  \sf{x \sqrt{2} }

If the diagonal of a square shrinks to 50 %

Then the new length of the diagonal after shrinking

 =   \displaystyle \:  \sf{ x \sqrt{2 }  -  \bigg(x \sqrt{2} \times  \frac{50}{100} \bigg) }

 =   \displaystyle \:  \sf{ \frac{x}{ \sqrt{2} }  }

So the new length of the side after shrinking

 =   \displaystyle \:  \sf{ \frac{x}{2 }  }

So the new area of the square is

 =   \displaystyle \: \sf{  { \bigg(  \frac{x}{2} \:  \bigg)}^{2} \: }

 =   \displaystyle \: \sf{  \frac{ {x}^{2} }{4}  }

So the shrinking in the area of the square

 =   \displaystyle \: \sf{   {x}^{2} -  \frac{ {x}^{2} }{4}  }

 =   \displaystyle \: \sf{  \frac{ 3{x}^{2} }{4}  }

So the percentage in shrinking of the area is

 =   \displaystyle \: \sf{   \frac{\frac{3 {x}^{2} }{4}}{ {x}^{2} }    \times 100 \%}

 =   \displaystyle \: \sf{  75 \%}

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

If a solid cube of total surface area is cut into 64 identical cubes, by what value would the total surface area increase

https://brainly.in/question/12961284

Similar questions