if the diagonal of bcc unit cell be 8√3.find the radius of the atom.
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Answer:
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Explanation:
In FCC: The atoms at the face diagonals touch each. If a is the edge length of cube and r is the radius of the atom.
So,
2
a=4r
⇒a=2
2
r
In bcc: The atoms at the body diagonal touch each other.
So,
3
a=4r
⇒a=
3
4
r
In simple cubic: The atoms at the corners touch each other.
So, a=2r
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