IF THE DIAGONAL OF RHOMBUS ARE 12CM AND 16 CM RESPECTIVELY, FIND ALL THE ANGLE.
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We know that the diagonals of a rhombus bisect at right angles.
Let A B CD be the rhombus and AC and B D bisect at O.
A O=16/2=8 CM
BO=12/2=6 CM
In right angled △AOB,
AB2=AO2+BO2
=82+62
AB2=64+36=100
AB=√100=10 cm
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