If the diagonal of rhombus are 8cm and 6cm,Find it’s perimeter.
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Answer:
The perimeter of the rhombus is 20 cm.
Step-by-step explanation:
Refer to the diagram attached.
Let ABCD be a rhombus.
Given the length of diagonals = 8 cm and 6 cm
Let AD = 8 cm and BC = 6 cm
We know that the diagonals of a rhombus bisect at right angles,
Therefore,
- AO = OD = 4cm and BO = OC = 3 cm
- ∠AOC = ∠AOB = ∠BOD = ∠DOC = 90°
Therefore, in Δ AOC, using Pythagoras Theorem,
(AO)² + (OC)² = (AC)²
=> 4² + 3² = (AC)²
=> 16 + 9 = (AC)²
=> 25 = (AC)²
=> AC = ±5
Since, length cannot be negative, AC = 5 cm
We know that in a rhombus, all the sides are equal.
Therefore, the perimeter of rhombus = 4 * Length of 1 side
=> Perimeter = 4 * AC
= 4 * 5
= 20 cm
Therefore, the perimeter of the rhombus is 20 cm.
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