Question

if the diagonal of the quadrilateral is 9 cm and the perpendiculars drawn to the diagonals are 4 cm 4.8 CM then the area of the quadrilateral is​

Answer 1

Answer:

1/2×9×(4+4.8)

=9×4.4

= 39.6

Answer 2

The area of the quadrilateral is 39.6 cm².

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Let's understand a few concepts:

To calculate the area of the given quadrilateral we will use the following formula of the area of a quadrilateral:

$\boxed{\bold{Area\:of \:quadrilateral = \frac{1}{2} \times diagonal \:length\times (sum\: of \:perpendicular\: heights)}}$

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Let's solve the given problem:

The length of the diagonal of the quadrilateral = 9 cm

The length of the perpendiculars drawn to the diagonal is 4 cm and 4.8 cm.

Therefore, by using the above formula, we get

The area of the quadrilateral is,

= $\frac{1}{2} \times 9 \times (4 + 4.8)$

= $\frac{1}{2} \times 9 \times8.8$

= $\bold{39.6\:cm^2}$

Thus, the area of the quadrilateral is 39.6 cm².

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